Complete the square for the expression x²+6x. What is the completed square form?
(x+3)² ā 9
(x+3)²
(x+3)² ā 6
(xā3)² + 9
Completing the Square is an algebraic method used to solve quadratic equations by transforming them into a perfect square trinomial. It is essential in understanding the relationship between rational and irrational numbers, as the process often reveals the nature of a quadratic equationās roots. This technique involves manipulating integers, square and square roots to rewrite the equation in a simpler form, which aids in finding exact solutions. In statistics, itās useful for least squares methods, providing insights into the numerical behavior of data. The method also helps in visualizing quadratic functions, revealing their minimum or maximum values.
Completing the Square is a method used to rewrite a quadratic equation of the form šš„²+šš„+š = 0 into a perfect square form (š„āš)² = š. This transformation makes it easier to solve for the roots of the equation by isolating š„. The process involves adding and subtracting a specific value derived from the coefficient of š„ to create a perfect square trinomial. Once in this form, the equation can be solved by taking the square root on both sides and then isolating š„.
Completing the Square is often used to factorize quadratic equations and identify their roots or zeros, especially when traditional factorization methods fail. A quadratic equation like šš„²+šš„+š=0 can sometimes be challenging to factor due to its complexity. In such cases, completing the square offers a viable solution.
If you have a quadratic equation that canāt be easily factorized, completing the square can rearrange it into a more manageable form. This approach involves rewriting šš„²+šš„+š as a perfect square trinomial, making it easier to solve for š„.
Hereās an example with a different quadratic equation:
Step 1:
Factor out the coefficient of š„2x2, which is 33:
3š„²+12š„+9 = 3(š„²+4š„+3)
Now, the coefficient of š„² is 1.
Step 2:
Find half of the coefficient of š„x in the factored expression.
Here, the coefficient of š„ is . Half of 4 is 2.
Step 3:
Square this number to find (4/2)² = 4.
Step 4:
Add and subtract 4 after the š„ term inside the parentheses:
3(š„²+4š„+4ā4+3)
Step 5:
Factorize the perfect square trinomial formed by the first three terms:
š„²+4š„+4 = (š„+2)²
So the expression becomes:
3((š„+2)²ā4+3)
Step 6:
Simplify the constant terms:
ā4+3 = ā1
So, the final expression is:
3((š„+2)²ā1) = 3(š„+2)²ā3
This completes the square for the expression 3š„²+12š„+9 as:
3(š„+2)²ā3
To summarize:
The formula for completing the square simplifies the process of converting a quadratic equation into its vertex form. For a quadratic expression šš„²+šš„+š, we can rewrite it using the formula š(š„+š)²+š, where š and šn are calculated as š = š/2šā and š = šāšĀ²/4šā. This approach allows us to quickly identify the vertex of the parabola represented by the quadratic equation. By substituting the values of šm and šn back into the formula, we transform the equation into a format that highlights the parabolaās vertex. For example, given 2š„²+8š„+5, we find š = 2 and š = ā3, which results in the equivalent form 2(š„+2)²ā3. This method provides a streamlined way to manipulate quadratic expressions and understand their geometric properties.
Given 3š„²+12š„+7
Given ā2š„²+4š„ā1
To complete the square in the expression šš„²+šš„+ša, we follow these steps:
To complete the square for a quadratic expression like šš„²+šš„+š, the first step is to factor out ša to normalize the coefficient of š„² to 1. This transforms the equation into š[š„²+ššš„+šš]. Focusing on the first two terms, š„² and (š/š)š„, we then calculate half the coefficient of š„, which is š/2šā. Squaring this value yields šĀ²/4šĀ²ā. We add and subtract this square inside the expression, creating a perfect square trinomial. The equation now looks like š„²+(š/š)š„ = (š„+š/2š)²āšĀ²4šĀ²ā. By substituting this back into the original equation, we obtain šš„²+šš„+š = š[(š„+š/2š)²āšĀ²4šĀ²]+š. Expanding this and simplifying gives the quadratic equation in completed square form: š(š„+š/2š)²+(šāšĀ²/4š). This transformation provides an easy way to see the vertex of the parabola described by the quadratic equation and simplifies further calculations.
The purpose of completing the square is to rewrite a quadratic expression in a different form, specifically š(š„+š)²+š. This transformation makes it easier to solve quadratic equations and identify the vertex of a parabola.
If the coefficient of š„² isnāt 1, factor out that coefficient from the quadratic and linear terms to normalize it to 1. For example, with 4š„²+8š„, factor out 4 to get 4(š„²+2š„).
Adding and subtracting the square helps create a perfect square trinomial. This trinomial can then be rewritten as a squared binomial, which is essential to putting the quadratic equation into the desired completed square form.
Completing the square is a method that can be used to derive the quadratic formula. It transforms the quadratic equation into a form where taking the square root directly reveals the values of š„.
Completing the Square is an algebraic method used to solve quadratic equations by transforming them into a perfect square trinomial. It is essential in understanding the relationship between rational and irrational numbers, as the process often reveals the nature of a quadratic equationās roots. This technique involves manipulating integers, square and square roots to rewrite the equation in a simpler form, which aids in finding exact solutions. In statistics, itās useful for least squares methods, providing insights into the numerical behavior of data. The method also helps in visualizing quadratic functions, revealing their minimum or maximum values.
Completing the Square is a method used to rewrite a quadratic equation of the form šš„²+šš„+š = 0 into a perfect square form (š„āš)² = š. This transformation makes it easier to solve for the roots of the equation by isolating š„. The process involves adding and subtracting a specific value derived from the coefficient of š„ to create a perfect square trinomial. Once in this form, the equation can be solved by taking the square root on both sides and then isolating š„.
Completing the Square is often used to factorize quadratic equations and identify their roots or zeros, especially when traditional factorization methods fail. A quadratic equation like šš„²+šš„+š=0 can sometimes be challenging to factor due to its complexity. In such cases, completing the square offers a viable solution.
If you have a quadratic equation that canāt be easily factorized, completing the square can rearrange it into a more manageable form. This approach involves rewriting šš„²+šš„+š as a perfect square trinomial, making it easier to solve for š„.
Standard Form: Start with a quadratic equation in standard form: šš„²+šš„+š = 0.
Isolate š„² and š„: If š (the coefficient of š„²) is not 1, divide the entire equation by ša to make the coefficient of š„² equal to 1.
Move šc: Move the constant term šc to the right side of the equation.
Find the Completing Term: Take half of the coefficient of š„, š/2ā, and then square it to get the completing term: (š/2)².
Add and Subtract the Completing Term: Add this completing term to both sides of the equation to keep the equation balanced.
Form a Perfect Square: The left side of the equation can now be factored into a perfect square trinomial, (š„+š/2)², which is equal to the right side.
Solve for š„: Take the square root of both sides and solve for š„. Remember to consider both the positive and negative square roots.
Simplify the Solution: Isolate š„ to find the solution(s).
Hereās an example with a different quadratic equation:
Step 1:
Factor out the coefficient of š„2x2, which is 33:
3š„²+12š„+9 = 3(š„²+4š„+3)
Now, the coefficient of š„² is 1.
Step 2:
Find half of the coefficient of š„x in the factored expression.
Here, the coefficient of š„ is . Half of 4 is 2.
Step 3:
Square this number to find (4/2)² = 4.
Step 4:
Add and subtract 4 after the š„ term inside the parentheses:
3(š„²+4š„+4ā4+3)
Step 5:
Factorize the perfect square trinomial formed by the first three terms:
š„²+4š„+4 = (š„+2)²
So the expression becomes:
3((š„+2)²ā4+3)
Step 6:
Simplify the constant terms:
ā4+3 = ā1
So, the final expression is:
3((š„+2)²ā1) = 3(š„+2)²ā3
This completes the square for the expression 3š„²+12š„+9 as:
3(š„+2)²ā3
To summarize:
Ensure the coefficient of š„² is 1.
Add and subtract (š/2š)² inside the parentheses.
Factorize the perfect square trinomial.
Simplify the expression to obtain the result.
The formula for completing the square simplifies the process of converting a quadratic equation into its vertex form. For a quadratic expression šš„²+šš„+š, we can rewrite it using the formula š(š„+š)²+š, where š and šn are calculated as š = š/2šā and š = šāšĀ²/4šā. This approach allows us to quickly identify the vertex of the parabola represented by the quadratic equation. By substituting the values of šm and šn back into the formula, we transform the equation into a format that highlights the parabolaās vertex. For example, given 2š„²+8š„+5, we find š = 2 and š = ā3, which results in the equivalent form 2(š„+2)²ā3. This method provides a streamlined way to manipulate quadratic expressions and understand their geometric properties.
Given 3š„²+12š„+7
Calculate š:
š = 12/2Ć3 = 12/6=2
Calculate š:
š = 7ā12²/4Ć3 = 7ā144/12 = 7ā12 = ā5
Substitute into the Formula:
Substitute š and š into the formula:
3š„²+12š„+7 = 3(š„+2)²ā5
Given ā2š„²+4š„ā1
Calculate š:
š = 4/2Ćā2 = 4/ā4 = ā1
Calculate š
š = ā1ā4²/4Ćā2 = ā1ā16/ā8 = ā1+2 = 1
Substitute into the Formula:
Substitute šm and š into the formula:
ā2š„²+4š„ā1 = ā2(š„ā1)²+1
To complete the square in the expression šš„²+šš„+ša, we follow these steps:
Normalize the Coefficient of š„2:
Factor out ša to make the coefficient of š„² equal to 1:
šš„²+šš„+š = š[š„²+ššš„+šš]
Analyze the First Two Terms:
Consider the terms š„² and (š/š)š„. The term š„² represents the area of a square with side length š„. The term (š/š)š„ represents the area of a rectangle with length š/šā and breadth š„.
Visualize the Problem Geometrically:
Draw a square with side length š„, giving it an area of š„². Then, add a rectangle next to it with length ššabā and breadth š„, forming a new composite shape.
Adjust the Rectangle into Two Identical Parts:
The rectangleās length š/šā can be split into two halves of š/2šā each. Attach these halves on either side of the original square to create a new shape.
Create a New Larger Square:
To complete the larger square, we need to fill in the missing square in the corner. The missing squareās side length is š/2šā, and its area is (š/2š)² = šĀ²/4šĀ²ā.
Add and Subtract the Missing Area:
Add and subtract the missing area inside the factored expression: š[š„2+(š/š)š„+šĀ²/4šĀ²āšĀ²/4šĀ²+š/š]ā
Factor the Perfect Square Trinomial:
The first three terms form a perfect square trinomial: š[(š„+š/2š)²āšĀ²/4šĀ²+š/š]
Simplify the Expression:
Simplify the expression further: šš„²+šš„+š = š(š„+š/2š)²+š(š/šāšĀ²/4šĀ²)
To complete the square for a quadratic expression like šš„²+šš„+š, the first step is to factor out ša to normalize the coefficient of š„² to 1. This transforms the equation into š[š„²+ššš„+šš]. Focusing on the first two terms, š„² and (š/š)š„, we then calculate half the coefficient of š„, which is š/2šā. Squaring this value yields šĀ²/4šĀ²ā. We add and subtract this square inside the expression, creating a perfect square trinomial. The equation now looks like š„²+(š/š)š„ = (š„+š/2š)²āšĀ²4šĀ²ā. By substituting this back into the original equation, we obtain šš„²+šš„+š = š[(š„+š/2š)²āšĀ²4šĀ²]+š. Expanding this and simplifying gives the quadratic equation in completed square form: š(š„+š/2š)²+(šāšĀ²/4š). This transformation provides an easy way to see the vertex of the parabola described by the quadratic equation and simplifies further calculations.
Normalize the Quadratic Coefficient:
If the coefficient of š„² isnāt 1, factor it out of the first two terms to ensure the quadratic coefficient is 1.
Add and Subtract the Missing Square:
Take half the coefficient of š„, square it, and add and subtract this value after the š„ term. This completes the square inside the expression.
Simplify into Completed Square Form:
Rewrite the expression in the form (š„+š)² by factoring the trinomial and adjust the constants outside to find the final expression in the form š(š„+š)²+š.
The purpose of completing the square is to rewrite a quadratic expression in a different form, specifically š(š„+š)²+š. This transformation makes it easier to solve quadratic equations and identify the vertex of a parabola.
If the coefficient of š„² isnāt 1, factor out that coefficient from the quadratic and linear terms to normalize it to 1. For example, with 4š„²+8š„, factor out 4 to get 4(š„²+2š„).
Adding and subtracting the square helps create a perfect square trinomial. This trinomial can then be rewritten as a squared binomial, which is essential to putting the quadratic equation into the desired completed square form.
Completing the square is a method that can be used to derive the quadratic formula. It transforms the quadratic equation into a form where taking the square root directly reveals the values of š„.
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Complete the square for the expression x²+6x. What is the completed square form?
(x+3)² ā 9
(x+3)²
(x+3)² ā 6
(xā3)² + 9
What is the completed square form of x²ā8?
(x+4)² ā 16
(xā4)²
(xā4)² ā 8
(xā4)²ā16
Complete the square for x² + 10x + 9. What is the completed square form?
(x+5)² ā 16
(x+5)²ā6
(x+5)²+6
(x+5)²ā9
What is the completed square form of x² ā 2x + 1?
(xā1)²
(xā1)²ā1
(x+1)²
(x+1)²ā1
Complete the square for x² + 4x ā 5. What is the completed square form?
(x+2)²ā9
(x+2)²+1
(x+2)²ā7
(x+2)²ā1
What is the completed square form of x² ā 6x + 8?
(xā3)²+2
(xā3)² + 1
(xā3)² ā 2
(xā3)²ā1
Complete the square for x² + 2x + 3. What is the completed square form?
(x+1)²+1
(x+1)²+2
(x+1)²+3
(x+1)²ā1
What is the completed square form of x² ā 4x ā 5?
(xā2)²ā7
(xā2)²+1
(xā2)²ā9
(xā2)²ā6
What is the completed square form of x² + 8x + 16?
(x+4)²
(x+4)²ā16
(x+4)²ā8
(x+4)²+16
Complete the square for x² + 6x + 10. What is the completed square form?
(x+3)²ā1
(x+3)² + 1
(x+3)²+4
(x+3)²+2
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